0=-4u^2-6u+4

Solution for 0=-4u^2-6u+4 equation:

0=-4u^2-6u+4

We move all terms to the left:

0-(-4u^2-6u+4)=0

We add all the numbers together, and all the variables

-(-4u^2-6u+4)=0

We get rid of parentheses

4u^2+6u-4=0

a = 4; b = 6; c = -4;
Δ = b2-4ac
Δ = 62-4·4·(-4)
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-10}{2*4}=\frac{-16}{8}
=-2
$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+10}{2*4}=\frac{4}{8}
=1/2
$